How to determine if my equation is equal to, less that or more then 0?
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Hi,
Im trying to solve 2nd order ODE's and determine if the solution is critically damped, over damped or under damped.
I rearranged the formula and inputted the equation to solve the quadratic equation (which works) however i cannot get the IF statement to tell me when if D=0, D<0 or D>0. Is this running into problems with the complex numbers?
Please could someone point me in the correct direction with the IF statements?
A section of the script can be seen below:
a = 1
b = 1
c = 1
D = sqrt((b^2/(4*a^2))-(c/a));
if D>0
disp('Over Damped')
elseif D<0
disp('Under Damped')
else D==0
disp('Critically Damped')
end
2 个评论
Jos (10584)
2019-10-14
Did you debug your code, by for instance, displaying D before the if statement (remove the semicolon)?
采纳的回答
J Chen
2019-10-14
- The result of sqrt((b^2/(4*a^2))-(c/a)) is a complex number. You can't compare it with 0 (a real number)
- The formula for damping ratio is probably wrong. Should it be b/(2*sqrt(a*c)?
2 个评论
J Chen
2019-10-14
The damping ratio is defined as r = b/(2*sqrt(a*c)) = b^2/(4*a*c). It is under damped if r<1 and critically damped if r=1, etc. Your error came from other programming error. It's not related to the formula.
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