Matlab Coder Stand Alone Executable Linking Third Party Libs

Question

Nurullah Akkaya 2019-10-15

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/485419-matlab-coder-stand-alone-executable-linking-third-party-libs

评论： Jeffrey 2024-3-21

I have the following file example from the coder page,

function core()
fprintf("Hello World!!\n");
coder.updateBuildInfo('addCompileFlags','-lcurl');
coder.updateBuildInfo('addSourceFiles','foo.c');
y = 0;
y = coder.ceval('foo', 10, 20);
fprintf("%f\n", y);
end

That I am trying to link libcurl into final executable. I supply the following main.c file,

#include <stdio.h>
#include <stdlib.h>
#include "core_initialize.h"
#include "core.h"
#include "core_terminate.h"
int main()
{
    core_initialize();
    core();
    core_terminate();
    
    return 0;
}

with the following foo.c

#include <stdio.h>
#include <stdlib.h>
#include <curl/curl.h>
double foo(double in1, double in2)
{
  return in1 + in2;
}
int call(){
   CURL *curl;
   CURLcode res;
   curl = curl_easy_init();
}

It only uses curl_easy_init just to test linking it does do anything usefull.

Then use the following commands to build the standalone executable on linux (libcurl is present on the system along with gcc i can compile programs linking curl just fine from bash).

cfg =  coder.config('exe');
cfg.CustomSource = 'main.c';
cfg.CustomInclude = ['"',pwd,'"'];
codegen -config cfg -report core

At the final linking stage it fails with undefined reference to curl easy init. If i edit the make file manually and add -lcurl to SYSTEM_LIBS variable along with -lm it compiles. I can see the curl flag passed to all compile targets except the one that links all togerher. It calls c compiler on all files but last step is ran with g++ instead of gcc even though all my files are C files.

What is the proper way to pass thirt party libraries to matlab coder?