Count the values inside a cell array considering another cell array

Hi given a cell
V={{[1,1,1,1;25,45,70,90],[2,2,2,2;78,112,146,180],[3,3,3,3;93,127,161,195],[4,4;70,100],[6;85],[9,9;85,110]},{[],[2,2,2,2;73,107,141,175],[3,3,3,3;83,117,151,185],[4,4,4,4;65,85,105,125],[6;85],[9,9,9;80,105,130]}};
and
C = vertcat(V{:});
X = ~cellfun('isempty',C);
F = @(x)sum(x(2,:)<=80);
F give us the value of which in each cell of V we exceed the value 80.
knowing this, I would like to consider R
R={{[1,1,1,1;0,-5,5,0],[2,2,2,2;34,-63,-47,-71],[3,3,3,3;34,-38,-67,-76],[4,4;20,10],[6;20],[9,9;25,-45]},{[],[2,2,2,2;34,-63,-37,-66],[3,3,3,3;34,-63,-57,-86],[4,4,4,4;20,-30,-35,-27],[6;20],[9,9,9;25,-40,-50]}};
and sum the absolute values of the second raw of each cell till the column where I've exceed 80 in V is met.
NOTE THAT V AND R have the same cell dimensions. In fact the first row of each cell in V and R are the same.
The result shoul be a matrix Y (2*6) that collect the absolute value sum of the second raw of each cell. 2 beacuse we have two cell in R, and 6 because in each cell there are 6 cell again.
Could someone help me?

2 个评论

Original question:
"F give us the value of which in each cell of V we exceed the value 80."
Actually the anonymous function F does not know anything about V, nor does it have anything to do with cell arrays. Also, you calculate X but do not use it anywhere.
Without the context of my answer those three lines are not very informative. It would be much better to just paste a link to your earlier question or to my answer.
Thanks for the comment!
May you help me Stephen?
I was thinking about substitute the first row of each cell of F with the second row of V. Then again invert the row in F and then reapeat the code you suggest me in the previous question, with sumabs instead of sum.
But do you know how to implement/substitute the rows?

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 采纳的回答

>> Rc = vertcat(R{:});
>> Vc = vertcat(V{:});
>> X = ~cellfun('isempty',Rc) & ~cellfun('isempty',Vc);
>> F = @(r,v) sum(r(2,v(2,:)<=80)); % without ABS
>> M = zeros(size(Rc));
>> M(X) = cellfun(F,Rc(X),Vc(X))
M =
0 34 0 20 0 0
0 34 0 20 0 25
Or if you really want to sum the absolute values:
>> F = @(r,v) sum(abs(r(2,v(2,:)<=80))); % with ABS
>> M = zeros(size(Rc));
>> M(X) = cellfun(F,Rc(X),Vc(X))
M =
10 34 0 20 0 0
0 34 0 20 0 25

6 个评论

May I ask just one more thing? In case I want to sum just the values in the second row of F that are positive (>0).
How could I modify the code?
Rc = cellfun(@(v) v(v >= 0), Rc, 'UniformOutput', false);
It could be a solution, but it's not a good solution for 2 things:
1) I should also substitute with zeros the negative values
2) cause it's better to leave the negative and just sum the positive later
But I have no idea of how to do it. I'm not familiar with cellfun
"In case I want to sum just the values in the second row of F that are positive (>0)"
In your original question you wanted to sum the second row of the matrices of R until "the column where I've exceed 80 in V is met". Now you have given a new condition, that you only want to sum the positive values.
Does your new condition completely replace the original condition (which I already showed you how to do), or is it in addition to the original condition (i.e. you want both conditions to be met)?
Just completely replace. So NO addition to the previous
Thanks for ask this !
>> C = vertcat(R{:});
>> X = ~cellfun('isempty',C);
>> F = @(x)sum(max(0,x(2,:)));
>> M = zeros(size(C));
>> M(X) = cellfun(F,C(X))
M =
5 34 34 30 20 25
0 34 34 20 20 25

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