how to plot a continuous signal
显示 更早的评论
I want to plot x(t) = cos(200*pi*t*u(t)) and define u(t) seprately and then plot x(-t),x(t/3)
i wrote this
x = @(t) cos(200*pi*t*u(t));
t = linspace(-1, 1);
figure(1)
plot(t, x(t))
grid
function y = u(x)
y=0;
if x>=0
y=1;
end
end
采纳的回答
Star Strider
2019-10-19
This should get you started:
u = @(t) t>=0;
x = @(t,u) cos(200*pi*t.*u(t));
t = linspace(-1, 1);
figure(1)
plot(t, x(t,u))
grid
Extending that:
u = @(t) t>=0;
x = @(t,u) cos(200*pi*t.*u(t));
t = linspace(-1, 1);
figure(1)
plot(t, x(t,u))
hold on
plot(t, x(-t,u))
plot(t, x(t/3,u))
hold off
grid
Experiment to get different results.
8 个评论
Mohammadreza kalantari
2019-10-19
Star Strider
2019-10-19
My pleasure.
Add: 1E-14 (or some similar small value) to whatever is in the denominator. That will still result in a very large number, however not Inf or NaN.
Note that in those instances, you need to use element-wise division, ./. See the documentation section on Array vs. Matrix Operations for a fulll discussion.
Mohammadreza kalantari
2019-10-26
Star Strider
2019-10-26
Try this:
A = 42; % Universal Answer (HHGTTG)
y = @(t) A*exp(1j*2*pi*t)
t = linspace(-1, 1);
figure
plot(t, real(y(t)),'-b', t, imag(y(t)), '--')
grid
legend('\Re', '\Im')
Experiment to get the result you want.
Mohammadreza kalantari
2019-10-31
编辑：Mohammadreza kalantari
2019-10-31
Star Strider
2019-10-31
This should be posted as a new Question.
Mohammadreza kalantari
2019-10-31
编辑：Mohammadreza kalantari
2019-10-31
Star Strider
2019-10-31
更多回答（1 个）
Asif
2024-4-4
0 个投票
t=0:0.01:5; %Time from 0 to 5 seconds with a step size of 0.01 seconds
%Define the continous signal ( for example, a sinusoidal signal)
% Frequency=2; %Frequency of the sinusoid in HZ
Amplitude=1; % Amplitude of the sinusoid
Phase = pi/4; %phase of the sinusoid ( in radians)
signal = Amplitude*sin(2*pi*Frequency*t+Phase);
% plot the continuous signal
plot(t, signal,'b','Linewidth',6);
xlabel('xTime(s)X');
ylabel('Ampltitude');
title('Continuous Sinusoidal signal');
grid on
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