Accessing timetable data using user defined column

6 次查看(过去 30 天)
Hello everyone. I just have a small doubt regarding accessing of timetable data.
For example, I have a timetable T as below
I am trying to access the value data as
T.value(2)
which gives me 15.
but I dont want to index it as T.value(1) or T.value(2) or T.value(3) to access the value data. Instead I want to use time_lin column.
like T.time_lin(0.4) which has to give the value data corresponding to it i.e 15.
I guess it would be possible. I have tried using many commands and ended up with errors.
I hope I could get some help. Thanks beforehand.

采纳的回答

Jon
Jon 2019-10-21
You can do something like this
v = T.value(T.time_lin==0.4)

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Data Type Conversion 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by