Change yticks using a stacked plot
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Hello,
I am using the stackedplot function to display multiple series of data that share the same x axis. I would like to change the y ticks, but I can't figure out how to do it. In this case, I would like to make the y tick marks go by 4,000. So basically the y axis should have the following tick marks: 0, 4000, 8000, 12000. Attached is the figure. I can't seem to find a tick mark property in this graph and using
yticks(0:4000:12000)
returns the following error:
Using xticks with stackedplot is not supported.
Thanks,
Clay
采纳的回答
Artemio Soto Breceda
2019-10-23
You should use the stackedplot with an output argument:
handle = stackedplot(rand(5)); % Plot 5 random vectors with 5 elements each
Then you can use the handle to change the properties of your figure:
handle.AxesProperties(1).YLimits = [0 12000]; % Changes the limits of the first plot
or in a for loop to change them all:
for i = 1:numel(handle.AxesProperties)
handle.AxesProperties(i).YLimits = [0 12000];
end
This does not quite control the ticks, instead it changes the limits of the axis, such as ylim([a b]) would do.
I do not think there is any property for stackedplot to do what you want, but this approach may suffice. Otherwise, I recommend you to use subplot and simply remove the xaxis of each subplot except for the last one.
for i = 1:5
h = subplot(5,1,i);
plot(rand(1,5)); % Plotting random numbers, here you put your data
if i < 5, h.XTick = [];end
box off
end
Then you can do what you want:
h.YTick = [0:4000:12000];
I think using subplot is a much better practice, because it gives you much more freedom.
2 个评论
Clay Swackhamer
2019-10-23
Joe Vinciguerra
2019-10-23
Stackedplot is comparatively new, and lacks a lot of the fine-tune-ability available in other plot types. But I would expect to see this and similar shortcomings addressed in future releases.
更多回答（1 个）
You can get the axis handles in stackedplot using the undocumented NodeChildren property. Then set YTick.
rng('default')
h = stackedplot(1:20, rand(20,4)*1000+500);
ax = findobj(h.NodeChildren, 'Type','Axes');
set(ax, 'YTick', [600:300:1500], 'YLim', [500,1600])
To set ytick of a selected axis number n,
% set(ax(n), ...)
3 个评论
Clay Swackhamer
2020-11-19
Eric Roden
2021-3-12
Yes, thank you, it took me a long time to find this, and am very happy I did!
Bradley Stiritz
2025-6-25
Thank you Adam!
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