Clipping sin wave script, what is not correct ?
显示 更早的评论
Write a script to generate the signal values for the figure above corresponding to equally-spaced time values ranging from 0 to 6*pi . Assign these time values to the variable Time. Assign the resulting voltage values to the variable signalVoltage. The sinusoidal function is given by the formula: Y=7sin(x) In order to model the clipping at plus or minus 5 Volts, you will need to replace any values of y that are greater than the threshold of 5 with the value 5. Similarly you will need to replace any values of y that are less than with the value -5
My attempt: Time= 0:6*pi Signal voltage = 7sin(time) Plot ( time, signal voltage) Signalvoltagelim([-5,5])
Don’t know what I am doing wrong. What in my script is wrong ?
采纳的回答
time=linspace(0,6*pi,500);
Y=7*sin(time);
figure()
subplot(121),plot(time,Y);
ylim([-8 8]);
Y(Y>5)=5; % You can replace by any value, here I have consider 5
Y(Y<-5)=-5% You can replace by any value, here I have consider -5
subplot(122),plot(time,Y);
ylim([-8 8]);
Or
time=linspace(0,6*pi,500);
Y=7*sin(time);
figure()
plot(time,Y);
hold on;
Y(Y>5)=5; % You can replace by any value, here I have consider 5
Y(Y<-5)=-5% You can replace by any value, here I have consider -5
plot(time,Y);
legend('Original','Clipping')
3 个评论
STUDENT
2019-10-23
KALYAN ACHARJYA
2019-10-23
编辑：KALYAN ACHARJYA
2019-10-23
Considering 500 vectors elements between 0 and 6Pi, you can choose any other number also
Emile
2023-8-2
🙏
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Instrument Control Toolbox 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
