array of natural numbers from 1 to n subset

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Sofija 2012-9-21

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I have array of natural numbers from 1 to n. They are divided into m groups with m-1 elements -> m*(m-1)=n. I need to make n/2-length array whose elements are all elements from first group, last m-2 elements from second group, last m-3 elements from third group...zero elements from last group. For example 5*4=20: x=[1:20] I need 1,2,3,4; 6,7,8; 11,12; 16; Thanks!

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Thomas 2012-9-21

Sounds like homework.. what have you done so far?

Sofija 2012-9-21

编辑：Walter Roberson 2012-9-21

在 MATLAB Online 中打开

well...nothing so far:)

only array [1 2 3 4 2 3 4 3 4 4]

unique=zeros(1,l/2);
ind=1;
for i=1:k-1
    for j=1:(k-1-i+1)
        unique(ind)=j+i-1;
        ind=ind+1;
    end
end 
    % code
  end

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Answer 1

Thomas 2012-9-21

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https://ww2.mathworks.cn/matlabcentral/answers/48739-array-of-natural-numbers-from-1-to-n-subset#answer_59583

编辑：Thomas 2012-9-21

在 MATLAB Online 中打开

Ok, there are multiple ways to go about, I'll suggest a start to one, but you will have to develop the logic yourself

First step: Create your array of n natural numbers for Eg

n=20;
your_array=[1:n]     % create your array
m=5;     % number of elements in groups

To split the array into subgroups, you might have to use for loops. Or oyu could just split the array using indexing into groups of m or (m-1) as you need. http://www.mathworks.com/company/newsletters/articles/Matrix-Indexing-in-MATLAB/matrix.html I'm showing the example with the reshape command, your output matrix to work with will be ( I for one, know when my students have used outside help when I see the reshape command used in an introduction to matlab code.. :))

a=reshape(your_array,m,n/m)'

Now you need the m-1 elements from row 1, m-2 from row 2 and so on..

a(1,1;m-1) % this is only for first row

Develop your logic for the completion of the code