calling more than 2 matrix for for loop
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A =
8 9
15 39
23 14
18 2
13 17
40 18
14 39
38 42
x1= A([1,2,3,5,8],:)
x2= A([1,2,3,4,8],:)
x3=A([1,2,3,5,7],:)
x4=A([1,2,3,4,5,8],:)
can i have a for loop which can call x1, x2,x3,x4 in an order
2 个评论
David Hill
2019-10-26
I am not sure what you mean, please explain more fully.
sampath kumar punna
2019-10-26
采纳的回答
David Hill
2019-10-26
Why not make a cell array?
x{1}= A([1,2,3,5,8],:);
x{2}= A([1,2,3,4,8],:);
x{3}=A([1,2,3,5,7],:);
x{4}=A([1,2,3,4,5,8],:);
for i=1:4
y{i}=x{i}/2;
end
2 个评论
sampath kumar punna
2019-10-26
David Hill
2019-10-26
Maybe I misunderstood you, it works for me and produces a cell array (y) having matrix elements that are the elements of x divided by 2.
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