calling more than 2 matrix for for loop

1 次查看（过去 30 天）
sampath kumar punna
sampath kumar punna 2019-10-26
评论： David Hill 2019-10-26
A =
8 9
15 39
23 14
18 2
13 17
40 18
14 39
38 42
x1= A([1,2,3,5,8],:)
x2= A([1,2,3,4,8],:)
x3=A([1,2,3,5,7],:)
x4=A([1,2,3,4,5,8],:)
can i have a for loop which can call x1, x2,x3,x4 in an order
  2 个评论
David Hill
David Hill 2019-10-26
I am not sure what you mean, please explain more fully.
sampath kumar punna
sampath kumar punna 2019-10-26
x1 =[
8 9
15 39
23 14
13 17
38 42]
x2 =[
8 9
15 39
23 14
18 2
38 42]
x3 =[
8 9
15 39
23 14
13 17
14 39]
x4 =[
8 9
15 39
23 14
18 2
13 17
38 42]
i have 4 matrices i want to call each matrix to get divided by 2
which is something like this
for i=1: 4
y(i)= x(i)/2
end
but this for loop is is not working beacuse location of x1,x2,x3,x4 is not fixed.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

David Hill
David Hill 2019-10-26
Why not make a cell array?
x{1}= A([1,2,3,5,8],:);
x{2}= A([1,2,3,4,8],:);
x{3}=A([1,2,3,5,7],:);
x{4}=A([1,2,3,4,5,8],:);
for i=1:4
y{i}=x{i}/2;
end
  2 个评论
David Hill
David Hill 2019-10-26
Maybe I misunderstood you, it works for me and produces a cell array (y) having matrix elements that are the elements of x divided by 2.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by