Output argument "y" (and maybe others) not assigned during call
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function y = ycal(x,x0,a)
gamma=0.021;
L=0.3*10^-2;
theta=0;
d=0.3*10^-3;
E=72*10^9;
I=3.976*10^-16;
A=2*gamma*cos(theta)*(2*a+d);
L1=x0;
offset=0.3*10^-3;
if(x<=L1)
y=(A/(E*I))*(x^3/6-(L1+a)*x^2/2)+offset;
elseif(L1<x&&x<=(L1+2*a))
T=(1+(L1)/2*a)/6;
U=(L1+a+(L1^2)/4*a)/2;
V=1/48*a;
W=L1^3/12*a;
X=L1^4/48*a;
y=(A/(E*I))*((x^3*T)-(x^2*U)-(x^4*V)+(x*W)-(1*X))+offset;
elseif((L1+2*a)<x&&x<=L)
Y=(L1^2+a*L1+(2/3)*a^2);
Z=((2/3)*L1^3+(2/3)*a^2*L1+(3/2)*a*L1^2+a^3/3);
y=(A/(E*I))*(-x*Y+Z)+offset
end
end
I'm getting this error"
Error in ycal (line 2)
gamma=0.021;
Output argument "y" (and maybe others) not assigned during call to "C:\Users\Admin\Documents\MATLAB\Proj\ycal.m>ycal"."
Could someone find the mistake please?
0 个评论
采纳的回答
Daniel M
2019-10-27
编辑:Daniel M
2019-10-27
What is the function supposed to return for y = ycal(1,0,0)? It doesn't pass any of the conditionals in the if statement. And since there is no default value for y, it cannot assign an output for y. Therefore, you need to handle the default value for y, perhaps by putting:
else
y = NaN;
end
Or something to that effect.
1 个评论
Star Strider
2019-10-27
Assign ‘y’ first:
function y = ycal(x,x0,a)
y = NaN;
gamma=0.021;
... REST OF THE CODE ...
end
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