How to cut dimensions of 3d arrays in a cell.

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BN
BN 2019-10-28
评论： Alex Mcaulley 2019-10-28
I have one 34*1 cell.
every array in it have 3 dimensions, all same (720*360*365)
I want to know how to cut all arrays like this: (700:720 * 300:360 * :)
cell.JPG

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采纳的回答

Yuan Li
Yuan Li 2019-10-28
B = cell(34,1);
for ii = 1:34
B{ii} = precips{ii}(700:720,300:360,:);
end
Then you will get a new cell, each element of the new cell is of size 21*61*365.

更多回答（1 个）

Alex Mcaulley
Alex Mcaulley 2019-10-28
Being A your cell array:
newA = arrayfun(@(i) A{i}(700:720,300:360,:),1:numel(A),'uni',0)
  2 个评论
BN
BN 2019-10-28
Thank you it's work, but it looks like transpose or something because if you look at the picture before using code all arrays are in a column but after using code all appear in row number 1 and different column. can you help me fix this problem and all arrays store in 1 column (just like firs picture in question)?
thank you
newA.JPG
Alex Mcaulley
Alex Mcaulley 2019-10-28
Then, you can transpose the cell array:
newA = arrayfun(@(i) A{i}(700:720,300:360,:),1:numel(A),'uni',0)'

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