How to eliminate Repeated NaNs in a array?

1 次查看(过去 30 天)
I have two vectors X, and Y; both will have NaNs present in them.
If X has a NaN, Y will have a NaN as well at the same location.
I would like to squeeze repepated NaNs to just one NaN.
For e.g. if X = [1,2.3, NaN, NaN, NaN, 2, 1].. then
X should be replaced by X=[1,2,3,NaN,2,1] and
Y also should reflect the same.
How would I achieve it?

采纳的回答

Adam Danz
Adam Danz 2019-10-28
% Demo data
x = [1:5 nan nan nan nan nan nan, 7:10, nan, 12, nan, 13:15, nan nan nan 19 ];
keepIdx = ~isnan(x); % keep all non-nans
keepIdx(logical([1,diff(~keepIdx)])) = true; % keep first of consecutive nans
x = x(keepIdx); % remove unwanted values from x
y = y(keepIdx); % remove unwanted values from y

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by