How to update matrix values using algorithm based on position?
显示 更早的评论
Suppose I've already create a square matrix, A=zeros(n).
Now let's say, for every position, A(i,j), I want to update the value to 1 / (i + j^2), can I do this easily?
Thanks!
采纳的回答
The straightforward way is to just use a loop:
A = zeros(n);
for ii = 1:n
for jj = 1:n
A(ii,jj) = 1/(ii+jj^2);
end
end
Here is another way to do it:
B = bsxfun(@(x,y) 1./(x+y.^2),(1:n).',1:n)
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
