How to update matrix values using algorithm based on position?

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Clark 2012-9-22

Suppose I've already create a square matrix, A=zeros(n).

Now let's say, for every position, A(i,j), I want to update the value to 1 / (i + j^2), can I do this easily?

Thanks!

Matt Fig 2012-9-22

编辑：Matt Fig 2012-9-22

The straightforward way is to just use a loop:

A = zeros(n);
for ii = 1:n
   for jj = 1:n
      A(ii,jj) = 1/(ii+jj^2);
   end
end

Here is another way to do it:

B = bsxfun(@(x,y) 1./(x+y.^2),(1:n).',1:n)

Clark 2012-9-22

Thanks. Can it be done without a loop?

Clark 2012-9-22

Thanks!

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