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How to find an equation of the tangent line to the curve f(x,y) =0 at the....

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Peter Pyrka
Peter Pyrka 2019-10-31
评论： darova 2019-10-31
the points (2.4, -2.7927) and (2.4, 2.7127)
f(x,y) = 4x + 2y -xy +3x^2 -5y^2 +5

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回答（1 个）

Mani Teja
Mani Teja 2019-10-31
Hello Peter,
This should help:
syms x y f(x,y)
f(x,y) = 4*x + 2*y -x*y +3*x^2 -5*y^2 +5;
a = f(2.4, -2.7927);
a = vpa(a,4); % Just to make it look better
b = f(2.4, 2.7127) ;
b = vpa(b,4);
Regards
Mani

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