How to perform right circular shift

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sadiqa ilyas
sadiqa ilyas 2019-11-4
评论： sadiqa ilyas 2019-11-5
Hi. I have written a code to perform circular shift but it does not give me all X28 and Y28 keys . It returns only one X28 and Y28 with out any circular shift.What I did wrong
key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
icount=0;
for i=1:16
icount=icount+R_key(i);
I=icount;
end
%circular shift
X28 = circshift(x', -icount)';
Y28 = circshift(y', -icount)';
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Walter Roberson
Walter Roberson 2019-11-4
sum(R_key) is 28, so icount is 28. That is the same as the length of your data, so you are circular shifting each bit of data exactly to the same place it started.
sadiqa ilyas
sadiqa ilyas 2019-11-4
Yes but I want all these outputs. 16 out puts after the circular shift performed according to R_key

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Walter Roberson
Walter Roberson 2019-11-4
key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
shift_counts = cumsum(R_key);
num_shifts = length(shift_counts);
x_shifted = zeros(num_shifts, length(x));
y_shifted = zeros(num_shifts, length(y));
for i = 1 : num_shifts
x_shifted(i, :) = circshift(x, -shift_counts(i));
y_shifted(i, :) = circshift(y, -shift_counts(i));
end

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