How to perform right circular shift
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Hi. I have written a code to perform circular shift but it does not give me all X28 and Y28 keys . It returns only one X28 and Y28 with out any circular shift.What I did wrong
key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
icount=0;
for i=1:16
icount=icount+R_key(i);
I=icount;
end
%circular shift
X28 = circshift(x', -icount)';
Y28 = circshift(y', -icount)';
3 个评论
Shubham Gupta
2019-11-4
what was the output that you were expecting?
Walter Roberson
2019-11-4
sum(R_key) is 28, so icount is 28. That is the same as the length of your data, so you are circular shifting each bit of data exactly to the same place it started.
sadiqa ilyas
2019-11-4
采纳的回答
Walter Roberson
2019-11-4
key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
shift_counts = cumsum(R_key);
num_shifts = length(shift_counts);
x_shifted = zeros(num_shifts, length(x));
y_shifted = zeros(num_shifts, length(y));
for i = 1 : num_shifts
x_shifted(i, :) = circshift(x, -shift_counts(i));
y_shifted(i, :) = circshift(y, -shift_counts(i));
end
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