What does the following code do?
显示 更早的评论
myFunction =@(x)x^2-6;
x_lower=0;
x_upper=5;
x_mid=(x_lower+x_upper)/2;
while abs(myFunction(x_mid))>0.01
if (myFunction(x_mid)*myFunction(x_upper))<0
x_lower =x_mid;
else
x_upper = x_mid;
x_mid=(x_lower+x_upper)/2;
end
x_mid=(x_lower+x_upper)/2;
end
fprintf('the root is %g; x_mid)
4 个评论
KALYAN ACHARJYA
2019-11-4
编辑：KALYAN ACHARJYA
2019-11-4
Which line do you have issue?
Raban Nghidinwa
2019-11-4
Star Strider
2019-11-4
So asking us to explain it to you is doing your homework for you, giving you an unfair advantage over your classmates who are doing this themselves, likely without any outside help.
Raban Nghidinwa
2019-11-4
采纳的回答
KALYAN ACHARJYA
2019-11-4
编辑：KALYAN ACHARJYA
2019-11-4
Here myFunction evaluates the value based on x
myFunction=@(x)x^2-6;
Say
myFunction(2), here x=2 passes to function arguments, so the result will
ans =
-2
Then
Assigned
x_lower=0;
x_upper=5;
x_mid=(x_lower+x_upper)/2;
While loop continue till Absolute(myFunction(x_mid)) is greater than 0.01
{
Then replace the value of x_mid, x_lower, x_upper based on if condition
If true
x_lower change to x_mid
otherwise
x_upper=x_mid;
x_mid=(x_lower+x_upper)/2;
end if
Re-evaluate x_mid again based on present x_lower and x_upper value
Then print the x_mid value
Note: Text the code with some example, change the my function expression and see the results
Hope it helps!
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