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Unable to store matrix array in for loop

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Prince Igweze
Prince Igweze 2019-11-5
回答： randerss simil 2021-2-13
t = linspace(10^-4,10^12,17)
for i = 1:17
m = inv((At * Cd * A) + (t(i) * Ht * H)) * At * Cd * do
end
Solution for m is a 20 by 1 matrix
but im having issues storing each iteration of the solution as an individual set (i.e m1 , m2, m3 ....m17)
it just lumps all the solutions as m
making it unable for me to call out a solution of choice
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Prince Igweze
Prince Igweze 2019-11-5
t is just a range of values between 10^-4 and 10^12
Prince Igweze
Prince Igweze 2019-11-5
that seems to make more sense.
Stephen, any ideas on how I can store each solution in the loop as M(1), M(2) .....M(17)
rather than M.

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回答（2 个）

Bhaskar R
Bhaskar R 2019-11-5
t = linspace(10^-4,10^12,17);
m = zeros(length(t),1); % initialize with zeros
for i = 1:17
m(i) = inv((At * Cd * A) + (t(i) * Ht * H)) * At * Cd * do; % store values for each iteration
end
  1 个评论
Prince Igweze
Prince Igweze 2019-11-5
its showing this when i run
Unable to perform assignment because the left and right sides have a different number of elements.

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randerss simil
randerss simil 2021-2-13
t = linspace(10^-4,10^12,17)
for i = 1:17
m{i} = inv((At * Cd * A) + (t(i) * Ht * H)) * At * Cd * do ; % use cell array
end
Use cell array as above

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