how to create a structure?
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I have a data set (DATA) that contains 100 stations with daily prices and demand.
Using this code I can have 100 stations with the data that belong to each of them.
Can you help me to fix the code??
N=length(DATA(:,1))
for i=1:N
x=DATA(i,1)
station=['S', num2str(x)]
station=[station;DATA(i,:)]
end
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Stephen23
2019-11-5
Using numbered variables is a sign that you are doing something wrong.
Indexing is simple and efficient (unlike what you are trying to do).
采纳的回答
Walter Roberson
2019-11-5
You can use num2cell to split the data into cell array by column.
You can construct an array of field names in a couple of ways, including using sprintfc or string objects with the + (concatenation) operation.
Once you have both of the above you can use cell2struct to create your structure.
However we wonder why you are not just leaving the data in the numeric matrix, as that is the fastest and smallest storage?
12 个评论
Walter Roberson
2019-11-5
I would suggest that you spend some time studying the documentation for accumarray(). It can take a bit of getting accustomed to, but it can be very useful.
Alternately you might want to read about findgroups(), and grpstats(), and splitapply(), which can do similar tasks in ways that are sometimes less cryptic.
(If you do use splitapply() then be sure to use @(x) mean(x,1) instead of just @mean, to account for the possibility that there might only be a single row of data for a combination.)
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