Load picture from folder

Question

ibleteus 2012-9-24

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I have write a code to load some pictures from special folder, unfortunately just load last picture.

The picture name is initially started from B19111 to finish B191110, according to this "*B-1911-k*" numbering .

    for a=1:10
          b=num2str(a);
          B{a}=imread(strcat('B1911',num2str(b),'.tif'));
    end

My questions: 1. The reason of error. 2. Why the B{a} in workspace show the info of picture?

thanks

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Romendra 2012-9-26

That is because B{} is a cell rather than a matrix. If you access the first part of the cell by B{1} it should show you the matrix associated with your image. As for the error what is the msg saying?

Thanks

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Answer 1

Image Analyst 2012-9-26

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编辑：Image Analyst 2012-9-28

在 MATLAB Online 中打开

See the examples from the FAQ: http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F. It does what you want to do. Here it is, slightly adapted for your situation:

% Read tiff files B19111.jpg through B191110.jpg.
folder = 'c:\whatever';  % Folder where your files live.  Could be pwd if they are in the current folder.
for k = 1 : 10
  imageFilename = sprintf('B1911%d.tif', k);
  fullFileName = fullfile(folder, imageFilename);
  if exist(fullFileName , 'file')
    fprintf('Processing image %s\n', fullFileName);
    imageArray{k} = imread(fullFileName);
  else
    fprintf('Image %s does not exist!\n', fullFileName);
  end
end

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Answer 2

Azzi Abdelmalek 2012-9-26

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    for a=1:10
         out{a}=imread(sprintf('B1911%d.tif',a))
    end

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Azzi Abdelmalek 2012-9-28

编辑：Azzi Abdelmalek 2012-9-28

在 MATLAB Online 中打开

   clear out
   for k=1:10
         out{k}=imread(sprintf('B1911%d.tif',k))
         figure
   imshow(out{k})
   end

Image Analyst 2012-9-28

You did something wrong. 'num2str(b)' should not be in quotes. But sprintf() is a better way than strcat() in my opinion. Have you looked at the FAQ? I adapted the code in there and posted it above for you in case you had difficulty doing that.

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Answer 3

Walter Roberson 2012-9-26

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Your code has

b = num2str(a);

and then in the next line uses num2str(b), thus trying to convert to string something that is already a string. The second line should use b instead of num2str(b)