how to write u= exp(1/((x-x_0)(x-x_1))) for x_0<x<x_1 using '@(x) function' in matlab?

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Kayode Odeyemi 2019-11-7

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/489691-how-to-write-u-exp-1-x-x_0-x-x_1-for-x_0-x-x_1-using-x-function-in-matlab

评论： Kayode Odeyemi 2019-11-7

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

u =@(x) vif(x>x0&x<x1,exp(1./((x-x0).*(x-x1))),0)

I need a function that can work with the @(x).

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Answer 1

Walter Roberson 2019-11-7

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/489691-how-to-write-u-exp-1-x-x_0-x-x_1-for-x_0-x-x_1-using-x-function-in-matlab#answer_400281

在 MATLAB Online 中打开

vif = @(condition, when_true, when_false) condition .* when_true + (~condition) .* when_false;

Note: this will not work if infinity is produced by the unselected side . For example, vif(x > 0, 1./x, 1) will not work for x = 0: even though the condition x>0 is not true for x=0, the 1./x would still be evaluated, giving inf, and when that was multipled by the 0 (false) of the condition x>0 that would be 0*inf which is nan.

If you need code that is able to handle the case where the expression might give infinity where the condition is not selected, then you will need a true function instead of an anonymous function. (Or you will need some obscure and ugly hacks involving subsexpr() and subsasgn() and multiple helper anonymous functions.)