Matlab Plotting Question: No graphs

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Meowooo
Meowooo 2019-11-8
回答： Artemio Soto Breceda 2019-11-8
1573185837(1).jpg
1573185869(1).png
Hello Everyone, I am trying to plot the below equilibrium curve by using the plot shown. However, my code does not work.
Is there anything that I missed? Thank you for your help! :)
  1 个评论
Shubham Gupta
Shubham Gupta 2019-11-8
your x1 & y1 are scalars. which is being plotted as a point on the graph.
plot(x1,y1,'r*')
Above code will show "red asterisk" at that point. But I sure you want x1 & y1 to be vectors, which you won't get unless you use vectors to calculate x1 & y1.

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采纳的回答

Hiroki Okawa
Hiroki Okawa 2019-11-8
编辑：Hiroki Okawa 2019-11-8
Hi, Meowooo
Please try below code.
T1 = 70:90; A1 = 13.8858; B1 = 2788.51; C1 = 220.79;
T2 = 120:140; A2 = 14.0045; B2 = 3279.47; C2 = 213.20;
P = 101.33;
P1sat = exp(A1 - B1 ./ (T1 + C1));
P2sat = exp(A2 - B2 ./ (T2 + C2));
x1 = ((P - P2sat)./(P1sat-P2sat)); % / => ./
y1 = (P1sat/P).*x1; % * => .*
plot(x1, y1);
grid on

更多回答（1 个）

Artemio Soto Breceda
Your problem is that x1 is a single value, rather than an array. It is actually plotting something, but it is just 1 single dot per element of y1. Try this and you will see what I mean:
plot(x1,y1,'o');
I believe that your problem would be fixed if you use the dot (.) operator to define x1:
x1 = ((P-P2sat)./(P1sat-P2sat)); % This makes x1 an array, instead of a single value
y1 = (P1sat/P).*x1; % Then you need to use the dot (.) operator on this line as well

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