Finding minimum value in while loop

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Takashi Fukushima
Takashi Fukushima 2019-11-9
评论： Takashi Fukushima 2019-11-9
Hello,
I would like to find the minimum value in what is calculated in while loop.
I have written a program so far...
speed=input("Enter the speed: ");
D=input("Enter the distance: ");
angle=5;
throwing_distance = (speed^2) * sin(pi * angle / 90) / 9.81;
deviation=abs(D-(speed^2) * sin(pi * angle / 90) / 9.81)
while angle<45
deviation=abs(D-(speed^2) * sin(pi * angle / 90) / 9.81);
angle=angle+1;
end
I would like to add if statement like,
if deviation is the minimum, display the angle.
I really appreciate if someone can help me solve this problem.

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回答（1 个）

Walter Roberson
Walter Roberson 2019-11-9
bestdeviation = inf;
while deviation < bestdeviation
bestdeviation = deviation;
deviation = abs(D-(speed^2) * sin(pi * angle / 90) / 9.81);
angle=angle+1;
end
  1 个评论
Takashi Fukushima
Takashi Fukushima 2019-11-9
Thank you very much for your response.
I came up with this solution...
speed=input("Enter the speed: ");
D=input("Enter the distance: ");
min_deviation=abs(D-(speed^2) * sin(pi * 5 / 90) / 9.81);
angle=5;
while angle<45
deviation=abs(D-(speed^2) * sin(pi * angle / 90) / 9.81);
next_deviation=abs(D-(speed^2) * sin(pi * (angle+1) / 90) / 9.81);
next_deviation2=abs(D-(speed^2) * sin(pi * (angle+2) / 90) / 9.81);
angle=angle+1;
if deviation>=next_deviation & next_deviation<=next_deviation2
disp("Optimal angle: " + angle);
disp("Optimal deviation: " + next_deviation);
end
end
disp("Optimal angle: " + 5 + " Optimal deviation: " + min_deviation);
In this way, I can get the optimal(minimum) deviation and its angle.
However, I need the last statement when the if statement is never true.
For example, the optimal angle and deviation of high speed and short D like (V>=100 and D<=10) are always 5 degree since the D is within the distance of 5 degree. However, the problem is that if the if statement is true, the program shows both optimal and minimal values
I know this is another topic, but if you can help me solve the problem, I would really appreciate.

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