find max value in a Matrix using loops only

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Zed Ferch
Zed Ferch 2019-11-10
评论： Zed Ferch 2019-11-10
hallo,
I can find only two max with this code. can you help me please to find all Max (more than 1 or 2) with the corrent code in this Matrix X=[1,2,3;7,1,9;4,9,6;9,8,7].
X=[1,2,3;7,1,9;4,9,6;9,8,7];
Max = -Inf;
row = 0;
column = 0;
row1 = 0;
column1 = 0;
for i = 1:size(X, 1)
for j = 1:size(X, 2)
if X(i, j) > Max
Max = X(i, j);
row = i;
column = j;
end
if X(i, j) >= Max
Max = X(i, j);
row1 = i;
column1 = j;
end
end
end
X
Max
row
column
row1
column1
  1 个评论
dpb
dpb 2019-11-10
Find global maximum first, then find the matching locations. Save the location indices in arrays instead of named variables. Mimic the output of the builtin max function.

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采纳的回答

JESUS DAVID ARIZA ROYETH
solution:
X=[1,2,3;7,1,9;4,9,6;9,8,7];
Max = -Inf;
row = [];
column = [];
for i=1:size(X,1)
for j=1:size(X,2)
if X(i,j)>=Max
Max=X(i,j);
end
end
end
for i=1:size(X,1)
for j=1:size(X,2)
if X(i,j)==Max
row(end+1)=i;
column(end+1)=j;
end
end
end
X
Max
row
column
  1 个评论
Zed Ferch
Zed Ferch 2019-11-10
Hallo Jesus David,
thank you very much for your help, the code word very well, thats nice :)

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