find max value in a Matrix using loops only
显示 更早的评论
hallo,
I can find only two max with this code. can you help me please to find all Max (more than 1 or 2) with the corrent code in this Matrix X=[1,2,3;7,1,9;4,9,6;9,8,7].
X=[1,2,3;7,1,9;4,9,6;9,8,7];
Max = -Inf;
row = 0;
column = 0;
row1 = 0;
column1 = 0;
for i = 1:size(X, 1)
for j = 1:size(X, 2)
if X(i, j) > Max
Max = X(i, j);
row = i;
column = j;
end
if X(i, j) >= Max
Max = X(i, j);
row1 = i;
column1 = j;
end
end
end
X
Max
row
column
row1
column1
1 个评论
dpb
2019-11-10
Find global maximum first, then find the matching locations. Save the location indices in arrays instead of named variables. Mimic the output of the builtin max function.
采纳的回答
JESUS DAVID ARIZA ROYETH
2019-11-10
solution:
X=[1,2,3;7,1,9;4,9,6;9,8,7];
Max = -Inf;
row = [];
column = [];
for i=1:size(X,1)
for j=1:size(X,2)
if X(i,j)>=Max
Max=X(i,j);
end
end
end
for i=1:size(X,1)
for j=1:size(X,2)
if X(i,j)==Max
row(end+1)=i;
column(end+1)=j;
end
end
end
X
Max
row
column
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