Why is MATLAB giving me the wrong Bode phase plot?
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I plotted
using
Z=[];
P=[1,-1];
K=100
G=zpk(Z,P,K);
G
bode(G)
And got
But it should be 0 deg not -180.
回答（1 个）
Urmila Rajpurohith
2019-11-14
0 个投票
The Bode Phase plot which you got is correct because the transfer function is written as
G=(-100)/((1+jw)(1+(-1)jw))
When you calculate phase angle then
For (1+jw) the phase angle is= -atan(w)
For (1+(-1)jw) the phase angle is which is -atan(-w) written as atan(w)-180
So, the overall phase angle becomes ɸ =-atan(w) + atan(w)-180
ɸ = -180
So, the Phase plot you will get at -180 deg.Here atan is nothing but inverse of tan.
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