Logical expression not working with loop and if statement
显示 更早的评论
I need an array with [1, 1, 0, 1, 0, 0, 1, 1, 0, 1]
N=10;
query_class=9;
n_candidate_class = [9, 9, 4, 9, 5, 5, 9, 9, 5, 9];
imgout = zeros(1,N);
for n = 1:N
for c = 1:N
if query_class == n_candidate_class(n)
imgout(c) = 1;
else
imgout(c) = 0;
end
end
end
3 个评论
Walter Roberson
2019-11-11
imgout = n_candidate_class == query_class;
is all that is needed if you want to process all of n_candidate_class
Maxence Boels
2019-11-11
Walter Roberson
2019-11-11
You overwrite each imgout(c ) for each different n value, so you are only getting the result as-if you had run with n=N . You want to be comparing corresponding values, not each one to each other.
采纳的回答
Hello Maxence Boels,
this is due to the inner for loop, which is causing problem. for n =1, the inner loop changes its values from 1 to 10, and compares query_class(whose value is 9) to n_candidate_class(1) which is also 9. Hence it return [1,1, 1,1,1,1,1,1,1,1] for the first iteration of n.
N=10;
query_class=9;
n_candidate_class = [9, 9, 4, 9, 5, 5, 9, 9, 5, 9];
imgout = zeros(1,N);
for n = 1:N
if query_class == n_candidate_class(n)
imgout(n) = 1;
else
imgout(n) = 0;
end
end
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