Logical expression not working with loop and if statement

1 次查看(过去 30 天)
I need an array with [1, 1, 0, 1, 0, 0, 1, 1, 0, 1]
N=10;
query_class=9;
n_candidate_class = [9, 9, 4, 9, 5, 5, 9, 9, 5, 9];
imgout = zeros(1,N);
for n = 1:N
for c = 1:N
if query_class == n_candidate_class(n)
imgout(c) = 1;
else
imgout(c) = 0;
end
end
end
  3 个评论
Maxence Boels
Maxence Boels 2019-11-11
Thank you ! Much simpler than I thought.
Do you know what was going wrong in my query?
Walter Roberson
Walter Roberson 2019-11-11
You overwrite each imgout(c ) for each different n value, so you are only getting the result as-if you had run with n=N . You want to be comparing corresponding values, not each one to each other.

请先登录,再进行评论。

采纳的回答

Ankit
Ankit 2019-11-11
编辑:Ankit 2019-11-11
Hello Maxence Boels,
this is due to the inner for loop, which is causing problem. for n =1, the inner loop changes its values from 1 to 10, and compares query_class(whose value is 9) to n_candidate_class(1) which is also 9. Hence it return [1,1, 1,1,1,1,1,1,1,1] for the first iteration of n.
N=10;
query_class=9;
n_candidate_class = [9, 9, 4, 9, 5, 5, 9, 9, 5, 9];
imgout = zeros(1,N);
for n = 1:N
if query_class == n_candidate_class(n)
imgout(n) = 1;
else
imgout(n) = 0;
end
end

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by