Assigning row to array using cellfun
显示 更早的评论
Hello,
I have a 1x4 cell array, each cell contains a 1000x8 zeros array:
A = arrayfun(@(~) zeros(1000,8),(1:4),'un',0);
Now I want to assign every same row (definded by a background counter) with a new array same length, e.g B = [1 1 1 1 1 1 1 1]
The following loop discribes it quite well...
counter = randi(1000) % any row
for i = 1:4
A{i}(counter,:) = B;
end
I was just wondering if there is a way doing it with cellfun?
1 个评论
JESUS DAVID ARIZA ROYETH
2019-11-11
maybe this code can help you
A=zeros(1000,1);
counter = randi(1000); % any row
A(counter)=1;
A=repmat({repmat(A,1,8)},1,4)
采纳的回答
Here's your loop, within cellfun().
A = cellfun(@(x)[x(1:counter-1,:);B;x(counter+1:end,:)], A, 'UniformOutput', false);
3 个评论
Konrad Warner
2019-11-11
编辑：Konrad Warner
2019-11-11
Adam Danz
2019-11-11
Really? I just timed the loop method from your question and the cellfun() method from my answer. Each method was repeated 100,000 times and each iteration was timed using tic/toc. When comparing the median speeds, the loop method was ~22 times faster than the cellfun method (I repeated that process twice and got nearly the same results).
The cellfun() method is (arguably) cleaner and reduces the number of lines of code but often times loops are faster than cellfun(), arrayfun() etc. I wonder if your timing test involved additional computations.
Konrad Warner
2019-11-12
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
