For loop only saving my last run
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for i = 1:2
Result(i) = norm(vcu(i,:))
end
p=0
for k = 1:2
ada = vcu(k,:)/Result(k)
end
Where vcu is a vector (a,b,c;a2,b2,c3)
when I run the code I get 2 1x3 vectors as ada but when I want to use ada further in my code it does not work because ada is only saved for k=2
1 个评论
David Hill
2019-11-13
ada(k) = vcu(k,:)/Result(k)%I think you just need to index ada.
回答（1 个）
Jyothis Gireesh
2019-11-18
Here are a few pointers which may help with your situation:
- As per the code given above each iteration of the for loop causes the result to be saved in the variable “ada”, which essentially overwrites the existing value. Since “ada” is not predefined, it takes the size of the last data assigned to it (1x3).
- Instead, you may use the following code:
ada = zeros(2, size(vcu, 2));
for k = 1:2
ada(k,:) = vcu(k,:)/Result(k);
end
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2019-11-18
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