A function to find prime number
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Hello,
I wrote a function to find a prime number and would like to run it to find all prime numbers up to 100 from my starting point. However, I get an error saying "too many output arguments".
Here is what I have...
function isPrime(number)
tf=isprime(number);
if tf==true
disp(number)
end
end
starting_point=input("Enter your number: ");
while starting_point<100
disp(isPrime(starting_point))
starting_point=starting_point+1;
end
I would really appreciate if anyone can help me with this problem....
采纳的回答
James Tursa
2019-11-13
编辑：James Tursa
2019-11-13
Your function doesn't return anything, so when you try to use its output you get an error. Change this:
function isPrime(number)
to this
function tf = isPrime(number)
3 个评论
Takashi Fukushima
2019-11-13
James Tursa
2019-11-14
Put a semi-colon at the end of the assignment line to suppress the output:
result=isPrime(number);
Takashi Fukushima
2019-11-14
更多回答（1 个）
John D'Errico
2019-11-13
Hey, you wrote some code! Credit for that. :-)
But what did you do?
function isPrime(number)
tf=isprime(number);
if tf==true
disp(number)
end
end
This function has NO outputs! None at all. It dumps somethign to the command window, but that is all. It does NOT return a result.
But then, how do you use it?
disp(isPrime(starting_point))
you use it, expecting an output.
What was the error message?
"too many output arguments"
So you wrote a function that returns no arguments, but then you used it expecting an output argument. Therein lies the problem. The fact is however, you are not using any output from isPrime, and it already dumps a comment to the command window.
Just change the code you use to this:
starting_point=input("Enter your number: ");
while starting_point<100
isPrime(starting_point)
starting_point=starting_point+1;
end
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