Taking means of initial values in individual cells of structure

Question

Rasmus Herlo 2019-11-15

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https://ww2.mathworks.cn/matlabcentral/answers/491367-taking-means-of-initial-values-in-individual-cells-of-structure

编辑： Daniel M 2019-11-17

This is my first question in here, so excuse for lacking syntax or structure:

I have a structure ('tracks') containing many fields (fx 'A'), and in each row there is a cell containing a track of 1000frames.

I would like to estimate the initial values of all traces, but since there are noise, I'd like to pull out the mean value of the three initial values instead of just the initial value.

I have looked around matlab and seems to be needing the right formulation of a cell-function, but neither of my attempts, fx:

Int = cellfun(@mean, {tracks.A(1:3)}, 'UniformOutput', false);

Int2 = cellfun(@(x) mean(x), tracks.A(1:3), 'UniformOutput',false);

seems to be working.

Can anybody tell me what I am missing here, and how to write it correctly, please?

-very much appreciated

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Answer 1

Daniel M 2019-11-16

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https://ww2.mathworks.cn/matlabcentral/answers/491367-taking-means-of-initial-values-in-individual-cells-of-structure#answer_401794

编辑：Daniel M 2019-11-17

在 MATLAB Online 中打开

tracks.A = [{1:6};{10:14}];
Int2 = cellfun(@(x) mean(x(1:3)), tracks.A);
% ans = [2; 11];

If instead you have a non-scalar struct:

tracks(1).A = [1:6]; 
tracks(2).A = [10:14];
Int2 = cellfun(@(x) mean(x(1:3)), {tracks.A});
% ans = [2; 11];

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Answer 2

Rasmus Herlo 2019-11-17

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https://ww2.mathworks.cn/matlabcentral/answers/491367-taking-means-of-initial-values-in-individual-cells-of-structure#answer_401929

Thanks for the effort Daniel. My tracks-structure was slightly different than the one you used, so that tracks(1).A = [1:1000], tracks(2).A = [1001:2000], etc...

Your suggestion therefore gave the error:

Error using cellfun

Input #2 expected to be a cell array, was double instead.

However, it gave the inspiration to put in the (1:3) in the rigth location, as:

Int2 = cellfun(@(x) mean(x(1:3)), {tracks.A}), so thank you

Would it now be good manners to accept your answer, or should I avoid it to prevent confusion?

Thanks