can i make a loop for mentioned equation?

2019 11 16
2 个回答
更新时间：2019 11 22
3 次查看（30 天）

0 个投票

hi everybody;
i want to find the value of (Pb_dis) from below equation and then make a loop to put (Pb_dis) value that i found from equation to (Pb1dis) to find (Pb_dis1) and to put the value of (Pb_dis1) to (Pb1dis) again to find (Pb_dis2) and so on . thank you very much i really appreciate it if you help me,
initial Pb1dis =3600 w
this is the equation:
Pb_dis= (Pb1dis*(1-sigma))-((Ppv/nu_i)-PL);

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David Hill
David Hill 2019-11-16
You did not describe the other variables/constants. What are sigma, Ppv, nu_i, PL?
Mamad Mamadi
Mamad Mamadi 2019-11-16
Thank you for your answer and spending your time ,
I share the entire equation with values. really appriciate it if you help me to solve this eq.
the original equation are:
Pb(t)= (Pb(t-1)*(1-sigma))-((Ppv(t)/nu_i)-PL(t)); %for li-ion battery discharging
Pb(t)= (Pb(t-1)*(1-sigma))+(Ppv(t)-(PL(t)/nu_i))*nu_b; %for li-ion battery Charging
Pb(t-1)= 3600 %SOC at the begining (Wh) >>watt hour
%Ppv(t) = 123.3 %Enegy of PV(photovoltaic ) (Wh)
%PL(t) = 60 %Load Demand (Wh)
sigma = 2 %Self_Discharge factor
nu_i = 0.9 %inverter effeciency
nu_b= 0.95 %battery effeciency
t=time
Mamad Mamadi
Mamad Mamadi 2019-11-22
Please I need your help. I appriciate it if you can help me thanks.

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回答（2 个）

0 个投票

It would be something like this :
Pb1dis =inf;
Pb_dis2=3600;
tol=0.0001;%tolerance
while abs(Pb_dis2-Pb_dis)>tol
Pb_dis=Pb1dis2;
Pb_dis2= (Pb1dis*(1-sigma))-((Ppv/nu_i)-PL);
end
disp(Pb_dis2)

2 个评论
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Mamad Mamadi
Mamad Mamadi 2019-11-16
Thank you for your answer and spending your time ,
I share the entire equation with values. really appriciate it if you help me to solve this eq.
the original equation is:
Pb(t)= (Pb(t-1)*(1-sigma))-((Ppv(t)/nu_i)-PL(t)); %for li-ion battery discharging
Pb(t)= (Pb(t-1)*(1-sigma))+(Ppv(t)-(PL(t)/nu_i))*nu_b; %for li-ion battery Charging
Pb(t-1)= 3600 %SOC at the begining (Wh) >>watt hour
%Ppv(t) = 123.3 %Enegy of PV(photovoltaic ) (Wh)
%PL(t) = 60 %Load Demand (Wh)
sigma = 2 %Self_Discharge factor
nu_i = 0.9 %inverter effeciency
nu_b= 0.95 %battery effeciency
t=time
Mamad Mamadi
Mamad Mamadi 2019-11-22
could you please help me again. I used your codes but didnt work and shared it again completely. i really appricaite it if you help me. thanks

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wang sir
wang sir 2019-11-16

0 个投票

HI,dude,I'm sorry,I can't answer you the question because I don't know how to use this software.But I wish we can make friends!

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