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Wrong answer for sine function

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Ellen Brown
Ellen Brown 2019-11-17
评论： Star Strider 2019-11-17
I am trying to create a function to evaluate sine at different values of t
function F = rforce(t)
F = 0.3 + 0.2.*sin(2.*pi.*t/365 - pi/2);
end
but this gives the incorrect answer when ran in matlab
  2 个评论
Star Strider
Star Strider 2019-11-17
It would appear that the units of ‘t’ are days, so ‘F’ would be with respect to years (or fractions of years).
What result do you want?
Ellen Brown
Ellen Brown 2019-11-17
I want F in respect to days, how would I do this?

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Star Strider
Star Strider 2019-11-17
Define ‘t’ in terms of days (or fractions of days).
Try this:
rforce = @(t) 0.3 + 0.2.*sin(2.*pi.*t/365 - pi/2);
tdays = 1:0.25:365.25; % One Year in 6-Hour Increments
figure
plot(tdays, rforce(tdays))
grid
xlabel('Days')
ylabel('r Force')
xlim([min(tdays) max(tdays)])

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