Display Markers At Specific Data Points

60 次查看(过去 30 天)
Greetings
when i run this comman
plot(t_010_tbc_r_002,stress_010_01,'-o','MarkerIndices',1:10:length(stress_010_01))
it gives me this error
Error using plot
There is no MarkerIndices property on the Line class.
Error in Results (line 194)
plot(t_010_tbc_r_002,stress_010_01,'--o','MarkerIndices',1:10:length(stress_010_01))
reasons???
  2 个评论
Erivelton Gualter
Erivelton Gualter 2019-11-18
It does not seems to be wrong.
Run the following code and see if it works fine:
x = linspace(0,10);
y = sin(x);
plot(x,y,'-o','MarkerIndices',1:5:length(y))
Tahir Afareen
Tahir Afareen 2019-11-18
same error
Error using plot
There is no MarkerIndices property on the Line class.
Error in New_Curve_02 (line 3)
plot(x,y,'-o','MarkerIndices',1:5:length(y))

请先登录,再进行评论。

采纳的回答

Star Strider
Star Strider 2019-11-18
The MarkerIndices name-value pair is relatively new.
If you do not have it, it is straightforward to do that with a second plot call:
figure
plot(t_010_tbc_r_002,stress_010_01,'-b')
hold on
plot(t_010_tbc_r_002(idx),stress_010_01(idx),'ob')
hold off
Experiment to get different results.
  2 个评论
Tahir Afareen
Tahir Afareen 2019-11-18
Thank you very much Star Strider. It works.
figure
plot(t_010_tbc_r_002,stress_010_01,'-b')
hold on
plot(t_010_tbc_r_002(1:10:length(t_010_tbc_r_002)),stress_010_01(1:10:length(stress_010_01)),'ob')
hold off

请先登录,再进行评论。

更多回答(1 个)

the cyclist
the cyclist 2019-11-18
编辑:Steven Lord 2023-10-25
The marker indices functionality was introduced in version R2016b. If you have an older version, then you'll get an error.
You can find a suggested work-around in this question.
[SL: fixed typo in version number]

类别

Help CenterFile Exchange 中查找有关 2-D and 3-D Plots 的更多信息

产品


版本

R2016a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by