Indexing how many times is an element repeated in a matrix in another array

1 次查看(过去 30 天)
Sorry if the wording in the title doesn't make sense. I'm still a noob to MATLAB.
Let's say I have an experiment order of A = [1 2 1 2 3 2 3 3 1].
I would like to make another array counting how many times each task is repeated in A.
The expected outcome would be B = [1 1 2 2 1 3 2 3 3].
Particularly, when 1 appeared the 2nd time in A(3), B(3) = 2. When 1 appeared the 3nd time in A(9), B(9)= 3. Same applies for the other numbers.
How can I achieve this? Any help is much appreciated. Thank you!

采纳的回答

Erivelton Gualter
Erivelton Gualter 2019-11-19
The following piece of code solve your problem:
arr = unique(A);
for i=1:length(arr)
n = arr(i);
B(A==n) = 1:length(find(A==n));
end
B
Next time, try to show some attempt code ;)
  1 个评论
Ningct12
Ningct12 2019-11-20
I was orginally planning to count them in a for loop using counter+1, but your method is much better! Thank you for your help! :)

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by