How to calculate the volume of a 3D triangular mesh?

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I have a pyramid with these vertices (each side is a triangle):
[-4 0 5;
1 -5 5;
1 0 1;
1 5 5;
1 0 0]
How can I calculate it's volume?
I couldn't quite understand this answer.
  5 个评论
Adam Danz
Adam Danz 2019-11-21
编辑:Adam Danz 2019-11-21
Even if I flip the z axis in my figure, it still doesn't produce the pyramid coordinates in the image in your comment above.
So, does your previous comment compute the volume of the pyramid would answers your question?
[update Re:PM]
Feel free to attach data to a comment or to your question. But more importantly, please clarify your question. Your code above seems to compute the volume so what problems are you having?
Hadi Ghahremannezhad
Yes, because there are also faces and edges in the mesh alongside the vertices.
The code does not compute the volume. The last comment is the part that I need to use the vertex positions to compute the volume of the whole mesh and put it in vol.

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采纳的回答

Ridwan Alam
Ridwan Alam 2019-11-21
编辑:Ridwan Alam 2019-11-21
Untitled1.png
Not quite sure I understood the problem. Yet, a hunch:
vertices = [-4 0 5;
1 -5 5;
1 0 1;
1 5 5;
1 0 0];
g = []; N = [];
for k = 1:size(vertices,1)
g = [g, sum(vertices(k,:))/3];
a = abs(vertices(k,1)-vertices(k,2));
b = abs(vertices(k,1)-vertices(k,3));
N = [N, a*b*sin(pi/3)]; % assuming theta = pi/3
end
Volume = sum(g.*N)/6;
  2 个评论
Hadi Ghahremannezhad
Do you know what the logical and sign means between two vectors? Is that the normal of two vectors?
Ridwan Alam
Ridwan Alam 2019-11-21
编辑:Ridwan Alam 2019-11-21
I believe that meant cross product of two vectors;
A ^ B = |A| |B| sin[theta]
Btw, please vote up if you liked the conversation!

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