How to calculate the volume of a 3D triangular mesh?
17 次查看(过去 30 天)
显示 更早的评论
I have a pyramid with these vertices (each side is a triangle):
[-4 0 5;
1 -5 5;
1 0 1;
1 5 5;
1 0 0]
How can I calculate it's volume?
5 个评论
Adam Danz
2019-11-21
编辑:Adam Danz
2019-11-21
Even if I flip the z axis in my figure, it still doesn't produce the pyramid coordinates in the image in your comment above.
So, does your previous comment compute the volume of the pyramid would answers your question?
[update Re:PM]
Feel free to attach data to a comment or to your question. But more importantly, please clarify your question. Your code above seems to compute the volume so what problems are you having?
采纳的回答
Ridwan Alam
2019-11-21
编辑:Ridwan Alam
2019-11-21
Not quite sure I understood the problem. Yet, a hunch:
vertices = [-4 0 5;
1 -5 5;
1 0 1;
1 5 5;
1 0 0];
g = []; N = [];
for k = 1:size(vertices,1)
g = [g, sum(vertices(k,:))/3];
a = abs(vertices(k,1)-vertices(k,2));
b = abs(vertices(k,1)-vertices(k,3));
N = [N, a*b*sin(pi/3)]; % assuming theta = pi/3
end
Volume = sum(g.*N)/6;
2 个评论
Ridwan Alam
2019-11-21
编辑:Ridwan Alam
2019-11-21
I believe that meant cross product of two vectors;
A ^ B = |A| |B| sin[theta]
Btw, please vote up if you liked the conversation!
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 3-D Volumetric Image Processing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!