Stopping a loop at the maximum value of y and finding the x from the maximum y

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Hi everyone,
How can i stop the loop when i get the maximum M(i) and how do i know what is the value of the x (phi) for the maximum value of M?
Thank You.
b=300; %mm
d=400; %mm
fc=40; %Mpa
Ecm=22*(fc/10)^0.3*10^3; %Mpa
Es=200000; %Mpa
As=2400; %mm^2
fy=400; %Mpa
epsc1=min(2.8/1000,0.7*fc^0.31/1000);
epscu=3.5/1000;
k=1.05*Ecm*epsc1/fc;
epscmv = linspace(0.05, 3.5, 50)*1E-3;
for i=1:50(epscmv);
epscm = epscmv(i);
funC=@(epsc) (k*epsc/epsc1-(epsc/epsc1).^2)./(1+(k-2)*epsc/epsc1);
compression=@(c) b*fc*c/epscm*integral(funC,0,epscm)/1000;
tension=@(c) min(Es*(d-c)/c*epscm*As/1000,fy*As/1000);
c(i)=fsolve(@(c) compression(c)-tension(c),1);
funM=@(epsc)(k*epsc./epsc1-(epsc./epsc1).^2)./(1+(k-2)*epsc./epsc1).*(d-c(i)+(c(i)./epscm).*epsc);
M(i)=b*fc*c(i)/epscm*integral(funM,0,epscm)/1000000;
phi(i)=epscm/c(i);
end
Mmax=max(M(i))
plot(phi, M)
grid on
xlabel('phi [1/mm]')
ylabel('Moment [kNm]')

采纳的回答

David Hill
David Hill 2019-11-23
b=300; %mm
d=400; %mm
fc=40; %Mpa
Ecm=22*(fc/10)^0.3*10^3; %Mpa
Es=200000; %Mpa
As=2400; %mm^2
fy=400; %Mpa
epsc1=min(2.8/1000,0.7*fc^0.31/1000);
epscu=3.5/1000;
k=1.05*Ecm*epsc1/fc;
epscmv = linspace(0.05, 3.5, 50)*1E-3;
for i=1:50(epscmv);
epscm = epscmv(i);
funC=@(epsc) (k*epsc/epsc1-(epsc/epsc1).^2)./(1+(k-2)*epsc/epsc1);
compression=@(c) b*fc*c/epscm*integral(funC,0,epscm)/1000;
tension=@(c) min(Es*(d-c)/c*epscm*As/1000,fy*As/1000);
c(i)=fsolve(@(c) compression(c)-tension(c),1);
funM=@(epsc)(k*epsc./epsc1-(epsc./epsc1).^2)./(1+(k-2)*epsc./epsc1).*(d-c(i)+(c(i)./epscm).*epsc);
M(i)=b*fc*c(i)/epscm*integral(funM,0,epscm)/1000000;
phi(i)=epscm/c(i);
end
[Mmax,idx]=max(M);%this is how you would get the max of M and the index at the maximum
phiAtmax=phi(idx);%using the index at maximum you can get the phi at the maximum
plot(phi, M)
grid on
xlabel('phi [1/mm]')
ylabel('Moment [kNm]')
  3 个评论
David Hill
David Hill 2019-11-23
If your function is smooth and has only one peak, then you can just check when the value is less than the previous value and break.
for i=1:50(epscmv);
epscm = epscmv(i);
funC=@(epsc) (k*epsc/epsc1-(epsc/epsc1).^2)./(1+(k-2)*epsc/epsc1);
compression=@(c) b*fc*c/epscm*integral(funC,0,epscm)/1000;
tension=@(c) min(Es*(d-c)/c*epscm*As/1000,fy*As/1000);
c(i)=fsolve(@(c) compression(c)-tension(c),1);
funM=@(epsc)(k*epsc./epsc1-(epsc./epsc1).^2)./(1+(k-2)*epsc./epsc1).*(d-c(i)+(c(i)./epscm).*epsc);
M(i)=b*fc*c(i)/epscm*integral(funM,0,epscm)/1000000;
phi(i)=epscm/c(i);
if M(i)<M(i-1)
break;
end
end
Shimon Katzman
Shimon Katzman 2019-11-23
doesnt work
Attempted to access M(0); index must be a positive integer or logical.
Error in advencedconcrete32a (line 22)
if M(i)<M(i-1)

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