Stopping a loop on the peak
1 次查看(过去 30 天)
显示 更早的评论
Hi
I want to stop the loop when i get to the peak of the M
b=300; %mm
d=400; %mm
fc=40; %Mpa
Ecm=22*(fc/10)^0.3*10^3; %Mpa
Es=200000; %Mpa
As=2400; %mm^2
fy=400; %Mpa
epsc1=min(2.8/1000,0.7*fc^0.31/1000);
epscu=3.5/1000;
k=1.05*Ecm*epsc1/fc;
epscmv = linspace(0.05, 3.5, 50)*1E-3;
for i=1:50(epscmv);
epscm = epscmv(i);
funC=@(epsc) (k*epsc/epsc1-(epsc/epsc1).^2)./(1+(k-2)*epsc/epsc1);
compression=@(c) b*fc*c/epscm*integral(funC,0,epscm)/1000;
tension=@(c) min(Es*(d-c)/c*epscm*As/1000,fy*As/1000);
c(i)=fsolve(@(c) compression(c)-tension(c),1);
funM=@(epsc)(k*epsc./epsc1-(epsc./epsc1).^2)./(1+(k-2)*epsc./epsc1).*(d-c(i)+(c(i)./epscm).*epsc);
M(i)=b*fc*c(i)/epscm*integral(funM,0,epscm)/1000000;
phi(i)=epscm/c(i);
if M(i)<M(i-1)
break;
end
end
[Mmax,idx]=max(M)
phiAtMmax=phi(idx)
plot(phi, M)
grid on
xlabel('phi [1/mm]')
ylabel('Moment [kNm]')
A kind forum member helped me but now I get the Error:
Attempted to access M(0); index must be a positive integer or logical.
Error in advencedconcrete32a (line 22)
if M(i)<M(i-1)
0 个评论
采纳的回答
Star Strider
2019-11-23
Change the if block to:
if (i > 1) & (M(i)<M(i-1))
break;
end
and your code appears to give the desired result.
This avoids the ‘zero index’ problem by comparing only the second and later values of ‘M’.
4 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!