Pressure as a function of crank angle

Question

Jonathan Bird 2019-11-23

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/492787-pressure-as-a-function-of-crank-angle

回答： Star Strider 2019-11-23

I need to plot pressure as a function of crank angle using the following eqaution p=(pm*SQRT(1-c^2))/(1-c*cos(alpha-delta)). Ive calculated all the required variables below but Im having trouble plotting with a for loop, any suggestions please?

V_se=7000;

V_sc=250;

v=V_sc/V_se;

T_e=333;

T_c=293;

t=T_c/T_e;

phi=pi/2;

T_r=312.6;

%let V_de=1000, V_r=500, V_dc=50

V_de=1000;

V_r=500;

V_dc=50;

V_d=V_de+V_r+V_dc;

T_d=324.7;

s=(V_d/V_se)*(T_c/T_d);

B=t+1+v+2*s;

A=sqrt(t^2-2*t+1+2*(t-1)*v*cos(phi)+v^2);

c=A/B;

p_m=1.01325;

%p_max=p_m*(sqrt(1+c)/sqrt(1-c));

%p_min=p_m*(sqrt(1-c)/sqrt(1+c));

delta=atan((v*sin(phi))/(t-1+v*cos(phi)));

for alpha=0:2*pi

p=(p_m*sqrt(1-c^2))/(1-c*cos(alpha-delta));

plot (alpha,p)

end,.,.

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Answer 1

Star Strider 2019-11-23

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/492787-pressure-as-a-function-of-crank-angle#answer_402977

在 MATLAB Online 中打开

Two options for the plot, depending on what you want to do:

Plot in the loop:

figure
hold all
for alpha=0:0.2:2*pi
  p=(p_m*sqrt(1-c^2))/(1-c*cos(alpha-delta));
  plot (alpha,p, 'p')
end
hold off
plot (alpha,p, 'p')
xlabel('\alpha')
ylabel('p')

Plot after the loop:

alpha=0:0.2:2*pi;
for k = 1:numel(alpha)
  p(k) = (p_m*sqrt(1-c^2))/(1-c*cos(alpha(k)-delta));
end
figure
plot (alpha,p, '-p')
xlabel('\alpha')
ylabel('p')