Can not get row vector to be 1,5

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Dylan Blosser
Dylan Blosser 2019-11-25
评论: Ridwan Alam 2019-11-28
I have written code to generate random numbers within a constrant and I just want the end result to be a row vector of 5 different times, not 6 different vectors adding one until it reaches 1,6. What do I need to change?
n=0;
for a=89:0.5:91.5;
n=n+1;
V(n)=2*rand+a
end

回答(2 个)

Adam Danz
Adam Danz 2019-11-25
编辑:Adam Danz 2019-11-25
First, here's the correct way to set up the loop. Avoid the n=n+1 approach in for-loops because for-loops are designed to iterate that way.
a = 89:0.5:91.5;
V = nan(size(a));
for i = 1:numel(a)
V(i)=2*rand+a(i);
end
Or, better yet, the vectorized version that does the entire thing in 1 line
V = 2 * rand(size(a)) + a;
But since 'a' contains 6 values, V will also contain 6 values. If you want 5 values, you'll need to redefine a.

Ridwan Alam
Ridwan Alam 2019-11-25
Because a=89:0.5:91.5 gives you a vector of length 6
n=0;
V = [];
for a=89:0.5:91
n=n+1;
V(n)=2*rand+a
end
  1 个评论
Ridwan Alam
Ridwan Alam 2019-11-28
Hi Dylan, please accept the response as an answer if it works. Thanks!

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