How Can i write a function that takes a structure array and returns this array with bubble sorting
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I want to write a function that takes a structure array holding information about students(name,age,gpa etc.) and returns this array by ordering the students with respect to their age by bubble sort.
function a=structarray (age,a)
for i=1:length(a)-1
if a(i).(age)>a(i+1).(age)
T=a(i);
a(i)=a(i+1);
a(i+1)=T;
i write this. but of course it is not working.pls guys help me.
4 个评论
Walter Roberson
2019-11-26
What inputs would be typical for the age parameter ?
By the way:
a([i, i+1]) = a([i+1,i]);
exchanges without needing any temporary variable.
Dart Min
2019-11-26
Walter Roberson
2019-11-26
When you call the function, passing in that a as the second parameter, what would you pass in as the first parameter?
What difficulties are you observing with your code?
Dart Min
2019-11-26
采纳的回答
Walter Roberson
2019-11-26
function a=structarray(a)
for i=1:length(a)-1
if a(i).age > a(i+1).age
T=a(i);
a(i)=a(i+1);
a(i+1)=T;
end
end
4 个评论
Dart Min
2019-11-26
Walter Roberson
2019-11-27
a(1).name='Matt';
a(1).age=22;
a(1).gpa=77;
a(2).name='Chris';
a(2).age=23;
a(2).gpa=45;
a(3).name='Park';
a(3).age=26;
a(3).gpa=81;
a(4).name='Stewie';
a(4).age=19;
a(4).gpa=44;
sorted_a = structarray(a);
Dart Min
2019-11-27
Walter Roberson
2019-11-27
That is because your bubble sort algorithm needs more work.
You only make a single pass through the data. But suppose the least age was in the last entry. Your code would exchange that with the second last entry, but would not then proceed to "bubble" that lowest age from the second last entry all the way back to the first entry.
更多回答（1 个）
Stijn Haenen
2019-11-26
Maybe this will work:
ages=[structurearray.age];
[a,b]=sort(ages);
newstructurearray=structurearray(b);
The used structure is attached.
3 个评论
Walter Roberson
2019-11-26
sort() is not a bubble sort.
Stijn Haenen
2019-11-26
Ah i missed that,
maybe this:
a(1).name='Matt';
a(1).age=22;
a(1).gpa=77;
a(2).name='Chris';
a(2).age=23;
a(2).gpa=45;
a(3).name='Park';
a(3).age=26;
a(3).gpa=81;
a(4).name='Stewie';
a(4).age=19;
a(4).gpa=44;
ages=[a.age];
[b]=unique(ages);
new_a=[];
for i=1:numel(b)
num=(ages==b(i));
new_a=[new_a;a(num)];
end
Walter Roberson
2019-11-27
That just pushes the sorting off into unique() but the assignment requirement is to use bubble sort.
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