while-loop condition - arrays equal within a tolerance

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Marko
Marko 2019-11-27
评论： Marko 2019-11-27
Hi guys!
I simplified the problem according to my issue. I basicly want to iterate arrays within a while function. But as soon as one element of the array is true, the while loop is not executed anymore. I want that the while looping is iterating until all elements of the arrays are euqal within a tolerance.
A = [5,2,1,0,0];
B = [4,1,0,0,0];
for i = 1:5
i = i+1
while not(A-B < 0.1*ones(5,1)) & ...
disp('Increase B')
B = B + 0.01;
end
end

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采纳的回答

Nicolas B.
Nicolas B. 2019-11-27
for you case, I understand that you want the maximum absolute difference being below a limit?
In that case, the "stay in" condition is:
while max(abs(A-B), [], 'all') > you_limit
...
end
the option on the max function is to ensure that you return 1 maximum whatever size have A and B.

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