Should i put the prices of (0.1-(v(i)*(x0+u(i)*x))^2) in a matrix and then find the max?
Possibly. You could vectorize,
(0.1-(v.*(x0+u.*x)).^2)
however it is not clear to me what max() is being taken with respect of. Is x possibly a vector?
If x is a vector then
max(0.1-(v(:).*(x0(:).'+u(:).*x(:).')).^2, 2)
would be the maximum over the x, in vectorized form. This requires R2016b or later to work as written.
The (:).' there are forcing whatever shape x0 and x are, to become row vectors. If you know for sure that x0 and x are row vectors then you can remove the (:).' operations (but you still need the (:) on v and u)
