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Convert a 3D image array into a cell array

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Nora
Nora 2012-9-28
Hi,
I know this will be basic for an experienced Matlab user but what I'm trying to do is convert an image stack, say a [mxnXp] matrix where p is the indexing dimension into a [px1] cell array.
My motivation for doing this originally was because I wanted to check to see which 'frames' of my image array were blank, i.e. equal to zeros(m,n).
I tried to use something like the following:
indices = find(arrayfun(@(IDX) ~isequal(IDX), isequal(imstack, zeros(size(imstack,1),size(imstack,2)))));
however this didn't work since imstack is a 3D matrix (at least this is why I suspect it didn't work)
To remedy I thought to convert imstack to a px1 cell array, with the view to using a 'cellfun' version of the above. And this is where I got stuck converting imstack to a cell array.
Any suggestions would be appreciated.
Thank you.
n

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Razvan
Razvan 2012-9-29
编辑：Razvan 2012-9-29
Try this:
blank = true(1,p);
for k = 1:p
if any(M(:,:,k))
blank(k) = false;
end
end
where M is your 3d matrix and p is the number of frames. You'll get in the end a vector blank which is true for the blank frames. To get the indices do
find(blank)

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Matt J
Matt J 2012-9-29
编辑：Matt J 2012-9-29
A more efficient approach than the for-loop would be
blank=~any(reshape(M,[],p),1);
Also, to put the slices of an array into cells, you can use this FEX file
http://www.mathworks.com/matlabcentral/fileexchange/35085-split-nd-array-into-equal-sized-cells
In your case, this would look like
Mcell=mat2tiles(M,[inf,inf,1]);
Mcell=Mcell(:); %make px1

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