About simple recursion code
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this code isn't work with me. for example i want to calculate the odd number in 9 is 5 odd number
function d = oddn(n)
%this program calculate the odd numbers in a number
if n==0 | mod(n,2)==0
d=0
elseif mod(n,2)~=0
d=1
else
d=oddn(n-1)+oddn(mod(n,2))
end
2 个评论
KALYAN ACHARJYA
2019-12-1
编辑：KALYAN ACHARJYA
2019-12-1
"i want to calculate the odd number in 9 is 5 odd number"?
Can you clarify again?
Shahad Alsabi
2019-12-1
采纳的回答
Turlough Hughes
2019-12-1
编辑：Turlough Hughes
2019-12-1
As I understand it you want to find the number of odd numbers from 1 to n. You shouldn't need to write a function for this, you can simply write:
d=ceil(floor(n)/2);
I used floor n, to account for circumstances where n is not an integer.
1 个评论
Turlough Hughes
2019-12-1
If recursion is a requirement you could do the following:
function d = oddn(n)
if n<=0
d=0;
else
d=oddn(n-1)+mod(n,2);
end
end
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