writing code so that for loop does not overwrite

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Cside 2019-12-1

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编辑： Cside 2019-12-1

Hi, I currently have this code and would like to NOT have the for loop overwrite with every t so that there will be 11 selectiven. How can i rewrite the problem line to make sure the for loop does not overwrite and produce 11 selectiven matrices? Thank you! :)

for t = 43:53
C= A(:,:,t); 
    for i = 1:8 
    D = find(sessions_pfc==i); 
        trialsize = size(trials(i).val); 
        B = ix_all(i); 
        B2 = cell2mat(B);
        [locations,~] = find(B2);
        anss = 0;
        for n = D(1,:):D(end) 
            p= anova1(C(n,1:trialsize(:,2)), locations', 'off');
            anss=anss+(p<0.05);
            selectiven (n,:) = p<0.05 
        end
    end 
neuronno(t) = find (selectiven); %%problem line
end 

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KALYAN ACHARJYA 2019-12-1

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https://ww2.mathworks.cn/matlabcentral/answers/494124-writing-code-so-that-for-loop-does-not-overwrite#answer_404090

编辑：KALYAN ACHARJYA 2019-12-1

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#Edited

neuronno(t) = find (selectiven);

As the t indices starts from 43 till 53. Here what about the previous indexing? Better to choose other variable name to avoid zeros or [ ] at initials-

%Drfine k=1 before first for loop
neuronno(k) = find (selectiven);
k=k+1; 

Still problem, let me kow?

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KALYAN ACHARJYA 2019-12-1

编辑：KALYAN ACHARJYA 2019-12-1

在 MATLAB Online 中打开

OK, May be in each iteration the following statement gives the same results

>> find(selectiven)
ans =
     1

Right? Is this statement complete? Based on my basic undestanding you may get the following results for neuronno

neuronno=[0 0 0 0 0.....................till 42 index then 1 1 1 1 1 1 1 1 1 1]

Cside 2019-12-1

every selectiven will be 226x1. However, find(selectiven) will give a different answer with each iteration as selectiven is a logical matrix, yielding an ans from 40-80.

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