arrays within for loop

2019 12 1
1 个回答
更新时间：2019 12 1
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0 个投票

for k=1:+1:4
S=(1/(k+1))*(m-b*y-m*r);
I=(1/(k+1))*(a*e-(m+r)*i);
y=y+(S*I);
end
I want to store values of S in ascending array and I in descending array then I'll get required y
can anyone help me with this code please.....

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回答（1 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2019-12-1
编辑：KALYAN ACHARJYA 2019-12-1

0 个投票

for k=1:4
S(k)=(1/(k+1))*(m-b*y-m*r); % How to get y here?
I(k)=(1/(k+1))*(a*e-(m+r)*i);
end
S=sort(S);
I=sort(I,'descend');
%Now Calculate Y
Or
y=zeros(1,4)
for k=1:4
S(k)=(1/(k+1))*(m-b*y(k)-m*r);
I(k)=(1/(k+1))*(a*e-(m+r)*i);
y(k+1)=y(k)+(S(k)*I(k));
end
S=sort(S);
I=sort(I,'descend');
% Canculate y again % I didnot find any sense here

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