Mapping two binary bits to one

I have generate a set of bits 0 and 1,
N=10000;
m=(sign(randn(1,N))+1)/2;
The problem is how do I group the bits? For example
00=-j
01=-1
10=1
11=j

1 个评论

No idea what you want, but look at dec2bin() and/or bin2dec().

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 采纳的回答

vals = [-1j, -1, 1, 1j];
m2 = reshape(m, 2, []);
idx = m2(1,:) * 2 + m(2,:) + 1;
output = vals(idx);

4 个评论

Hi, from the complex symbols, any method that I can get back to orignal binary number which contain 0 and 1?
ismember to get an index. Use that as a row index into a 4x2 array.
[, idx] = ismember(Symbols, [-1j, -1, 1, 1j]);
bits = [0 0; 0 1; 1 0; 1 1] .';
bit_vector = reshape(bits(:, idx), 1, []);

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