Hello all,
i am currently working on a project and I need your help.
I have an array with around 500 x 500 elements. The elements are values from 0,1...255.
I need something to compare nearby elements in this array.
The comparsion should work like this:
for i=1:size(A)
for j=1:size(A)
If current_element>=Tresh & previous_element>=Tresh & next_element>=Tresh
B(i) = A(i);
elseif current_element>=Tresh & next_element>=Tresh & next_after_next_element>=Tresh
B(i) = A(i);
elseif second_to_last_element>=Tresh & last_element>=Tresh & current_element>=Tresh
B(i) = A(i);
elseif ...
else B(i,j) = 0;
end
for example:
A = [4 0 0 0 3; 6 0 0 9 2; 6 7 9 8 1; 6 0 0 6 4; 0 10 0 0 0];
the result should be:
B = [0 0 0 0 0; 6 0 0 9 0; 6 7 9 8 0; 6 0 0 6 0; 0 0 0 0 0];
this example already has a threshold which only indicates elements equal to or greater than 5
I tried different posibilites but could not find any solution for my problem. I read a lot about the "Game of Life"-problem but think this is not suitable for my problem.
What i have tried so far is following code:
A = [4 0 0 0 3; 6 0 0 9 2; 6 7 9 8 1; 6 0 0 6 4; 0 10 0 0 0];
B=double(A);
Thresh=5;
for i=1:size(A)
for j=1:size(A)
if A(i)>=Thresh & A(i+1)>=Thresh
B(i) = A(i);
elseif A(j)>=Thresh & A(j+1)>=Thresh
B(j) = A(j);
else B(i,j) = 0;
end
end
end
and the result is:
B = [0 0 0 0 0; 6 0 0 9 2; 6 7 9 8 1; 0 0 0 0 0 ;0 10 0 0 0]
As you can see, it almost works how I need it. Unfortunateley values above 9 are a problem because they are not replaced by 0 if possible.
What can I do to refer to the second to last, previous and next after next element?
I know that for example
elseif A(i)>=Thresh & A(i+1)>=Thresh & A(i+2)>=Thresh
and
elseif A(i)>=Thresh & A(i-1)>=Thresh & A(i-2)>=Thresh
will not work.
I know that '-2' or similar is not working due to logical issues. But why '+2' as well?
Thanks in advance
