What is the meaning of this line?

Question

vimal kumar chawda 2019-12-3

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/494603-what-is-the-meaning-of-this-line

评论： Walter Roberson 2019-12-5

采纳的回答： KALYAN ACHARJYA

在 MATLAB Online 中打开

Hello

I want to know why we are using the line

sumX2=sumX2+(listOfPoints(1,i)-Xc(1,:))^2;

Why 2 times sumX2, and what is the purpose of using 2 times, and can anyone let me know?

What are the changes in the result ?

sumX2=0; sumY2 =0; sumZ2=0; sumXY=0; sumYZ=0; sumXZ=0;
    for i=1:N
        sumX2 = sumX2 + (listOfPoints(1,i)-Xc(1,:))^2;
        sumY2 = sumY2 + (listOfPoints(2,i)-Xc(2,:))^2;
        sumZ2 = sumZ2 + (listOfPoints(3,i)-Xc(3,:))^2;
        sumXY = sumXY + (listOfPoints(1,i)-Xc(1,:))*(listOfPoints(2,i)-Xc(2,:));
        sumYZ = sumYZ + (listOfPoints(2,i)-Xc(2,:))*(listOfPoints(3,i)-Xc(3,:));
        sumXZ = sumXZ + (listOfPoints(1,i)-Xc(1,:))*(listOfPoints(3,i)-Xc(3,:));
    end

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Answer 1

KALYAN ACHARJYA 2019-12-3

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/494603-what-is-the-meaning-of-this-line#answer_404519

编辑：KALYAN ACHARJYA 2019-12-3

在 MATLAB Online 中打开

"why 2 times sumX2 and what is the purpose of using 2times and can anyone do let me know?"

sumX2=sumX2+...

Here sumX2 updated during entire iteration

Let say example

sumX2=1;
for i=1:4;
sumX2=sumX2+i;
end 

#

In first Iteration, ehen i=1 
sumX2=sumX2+i=1+1=2
In 2nd Iteration, ehen i=2, sumX2=2
sumX2=sumX2+i=2+2=4
...so on..

In each ireration sumX2 used the last updated values, for current sumX2 calculation

Hope it helps!

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KALYAN ACHARJYA 2019-12-5

Great!

Keep Learning Vimal

Walter Roberson 2019-12-5

在 MATLAB Online 中打开

But i am getting only one value in this loop as respective row.

The expression (1/N)* sum(listOfPoints(1,:)) would sum the row vector listOfPoints(1,:) resulting in a scalar, and then would divide the scalar by N, resulting in a scalar. You then assign the result to Xc(1,:) which would assign the same scalar to all columns that exist in the first row of Xc. If, for example, Xc already existed with 17 columns, then all 17 columns of the first row will be assigned the exact same mean value.

The code I suggested,

Xc = mean(listOfPoints, 2);

is a little different in that it will result in Xc being exactly one column wide, no matter how big the existing Xc was. If you really need Xc to keep the same number of columns and have each column be exactly the same within each row, then there are a number of different was to achieve that, including,

Xc = mean(listOfPoints, 2) * ones(1, size(Xc,2));

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