Finding length between two array elements.

2019 12 3
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更新时间：2019 12 3
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i have an array consisting of 1's and 0's. 1-> generators on and 0's-> generators off. I need to find lengths for which the generators remain off. the array is 44*8760 values. Attaching the file as worspace.

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Hank
Hank 2019-12-3
Could you describe what you mean by the lengths?
Hrishikesh Dalal
Hrishikesh Dalal 2019-12-3
So, the number of zeros represent the hours for which the generator is off. See attachment. So i need to find the lenghts of all the zeros (all the hours for which generator is off) . In the screnshot, the first column for which zeros are ocurring has a count of 7. and then 1's followed by again zeros for which the count is 6. It simply means, my generator is off for 7 hours then its switching on and again off for 6 hours. this is what i need for all generators.
David Goodmanson
David Goodmanson 2019-12-3
编辑：David Goodmanson 2019-12-3
HI Hrishikesh,
for a single row of values x,
z = diff(find(diff([inf x inf])))
za = z(1:2:end)
zb = z(2:2:end)
gives a set of 'on' lenghts and a set of 'off' lengths. Which is which,
depends on whether x starts off with a 0 or a 1. With the aid of a small example you can work that out.
Hrishikesh Dalal
Hrishikesh Dalal 2019-12-3
Thanks for the reply David i will work it out
David Goodmanson
David Goodmanson 2019-12-3
Hrishikesh,
I posted the wrong expression for z in the comment but it is fixed now.

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the cyclist
the cyclist 2019-12-3

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The RunLength utility from the File Exchange might be handy. Run it in a loop over each column.

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